Original link: https://www.shuizilong.com/house/archives/luogu-p2050-noi2012-%E7%BE%8E%E9%A3%9F%E8%8A%82/

You can get 60 points by using the method of the previous question , and consider optimization. We found that for each chef, the edge it uses must be a set of prefixes, so it can be greedy to add new edges dynamically after each augmentation.
#include <lastweapon/io>
#include <lastweapon/mincostflow>
using namespace lastweapon;
int main() {
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
#endif
int n, m, p; RD(n, m); p = 800; int s = n+m*p, t = s+1, nn = 0;
mcf_graph<int, int> G(t+1);
REP(i, n) G.add_edge(s, i, RD(), 0);
REP(i, p) REP(j, m) G. add_edge(n+p*j+i, t, 1, 0);
REP(i, n) REP(j, m) {
int c; RD(c); REP(k, p) G.add_edge(i, n+p*j+k, 1, (k+1)*c);
}
printf("%d\n", G.flow(s, t).se);
}
This article is reproduced from: https://www.shuizilong.com/house/archives/luogu-p2050-noi2012-%E7%BE%8E%E9%A3%9F%E8%8A%82/
This site is only for collection, and the copyright belongs to the original author.